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Draw the graph of y=log(e)3x and compare...

Draw the graph of `y=log_(e)3x` and compare with `y=log_(e)x`.

Text Solution

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To draw the graph of `y=log_(e)3x` we draw the graph of `y=log_(e)x` and compress it '3' times horizontally.
That is, if any point (a,b) lies on the graph of `y=log_(e)x`, then we have the corresponding point (a/3,b) on the graph of `y=log_(e)x`.

In the above figure, `y=log_(e)x` is drawn for `x in(0,6)`
For `y=log_(e)3x` we must have `0lt3xle6,i.e.,0ltxlt2`.
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