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Draw the graph of |x|+|y|=1+x....

Draw the graph of `|x|+|y|=1+x`.

Text Solution

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We have `|x|+|y|=1+x`
or `|y|=1+x-|x|`
Let us first draw the graph of `y=f(x)=1+x-|x|`
Now `y=f(x)={{:(1+2x",",xlt0),(1",",xge0):}`
Graph of the above function is as shown in the following figure.

So the graph of `|y|=1+x-|x|` is as shown in the following figure.
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