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(log)(x-1)x (log)(x-2)(x-1) .....(log)(...

`(log)_(x-1)x (log)_(x-2)(x-1) .....(log)_(x-12)(x-11)=2,x` is equal to:

A

9

B

16

C

25

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`log_((x-12)) x = 2`
` x = (x-12)^(2)`
` x ^(2) - 25_(x) + 144 = 0`
` x = 9, 16`
but ` x ne 9, x = 16`
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