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If log2x+logx2=10/3=log2y+logy2 and x!=y...

If `log_2x+log_x2=10/3=log_2y+log_y2` and `x!=y` ,then `x+y=`

A

a.2

B

b.`65//8`

C

c.`37//6`

D

d.none of these

Text Solution

Verified by Experts

The correct Answer is:
D
`10/3 = 3 + 1/3*`The given equation is of the form
` p+1/p=3+1/3 = q + 1/q ," where "p ne q" as " x ne y`
` rArr log_(2) x=3, log_(2)y = 1//3" "(.:' x ne y)`
` rArr x = 2^(3), y=2^(1//3`
`:. X + y = 8+2^(1//3`
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