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Find the angle between the planes 2x+y...

Find the angle between the planes `2x+y-2z+3=0a n d 6x−2y+3z=5

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Normals along the given planes are `2hati+hatj-2hatk and 6hati+3hatj+2hatk`.
Then angle between planes, `theta = cos^(-1)=((2hati+hatj-2hatk)*(6hati+3hatj+2hatk))/(sqrt((2)^(2)+(1)^(2)+(-2)^(2))sqrt((6)^(2)+(3)^(2)+(2)^(2)))=cos^(-1)""(11)/(12)`
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