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Find the angle between the line (x-1)...

Find the angle between the line `(x-1)/3=(y-1)/2=(z-1)/4` and the plane `2x+y-3z+4=0.`

Text Solution

Verified by Experts

The angle between a line and a plane is complement of the angle between the line and the normal of the plane, i.e., 3, 2, 4 and normal 2, 1, -3. Therefore,
`" "costheta=(6+2-12)/(sqrt(29)*sqrt(14))=-(4)/(sqrt(406))`
`" "theta=cos^(-1) (-4//sqrt(406))`
`" "phi=90^(@)-theta`
`" " = 90^(@)- cos^(-1) * (-4//sqrt(406))`
`" " = sin ^(-1) (-4//sqrt(406))`
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Find the angle between the line (x-1)/(3)=(y+1)/(2)=(z+2)/(4) and the plane 2x+y-3z+4=0 .

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Knowledge Check

  • The angle between the line (x-1)/(2)=(y-2)/(1)=(z+3)/(-1) and the plane x+y+4=0 is __

    A
    `45^(@)`
    B
    `60^(@)`
    C
    `30^(@)`
    D
    `75^(@)`
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