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The line (x-2)/3=(y+1)/2=(z-1)/1 interse...

The line `(x-2)/3=(y+1)/2=(z-1)/1` intersects the curve `x y=c^(2),z=0` then `c` is equal to a. `+-1` b. `+-1//3` c. `+-sqrt(5)` d. none of these

A

`ne1`

B

`+-1//3`

C

`+-sqrt5`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
c
We have z=0 for the point, where the line intersects the curve. Therefore,
`(x-2)/(3)=(y+1)/(2)=(0-1)/(-1)`
`implies(x-2)/(3)=1and(y+1)/(2)=1`
`impliesx=5andy=1`
Putting these valese in `xy=c^(2)` we get
`5=c^(2)orc=+-sqrt5`
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