The value of m for which the straight li...

The value of m for which the straight line 3x-2y+z+3 = 0=4x-3y+4z+1. is parallel to the plane 2x-y+mz-2 = 0 is

-2

-18

Text Solution

Verified by Experts

The correct Answer is:

Vector `((3hati-2hatj+hatk)xx(4hati-3hatj+4hatk))` is perpendicular to `2hati-hatj+mhatk`. Thus,
`|[3,-2,1],[4,-3,4],[2,-1,m]|=0orm=-2`

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