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The point on the line (x-2)/1=(y+3)/(-2)...

The point on the line `(x-2)/1=(y+3)/(-2)=(z+5)/(-2)` at a distance of 6 from the point `(2,-3,-5)` is a. `(3,-5,-3)` b. `(4,-7,-9)` c. `(0,2,-1)` d. none of these

A

(3,-5,-3)

B

(4,-7,-9)

C

(0,2,-1)

D

(-3,5,3)

Text Solution

Verified by Experts

The correct Answer is:
b
Direction cosines of the given line are `(1)/(3)-(2)/(3)-(2)/(3)` Hence, the equation of line can be a point in the form
`(x-2)/(1//3)=(y=3)/(-2//3)=(z+5)/(-2//3)=r`
Therefore, any point on the line is
`(2+(r)/(3),-3-(2r)/(3),-5-(2r)/(3)),"where "r-pm6`. Points are (4,-7,-9) and (0,1,-1)
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