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The radius of the circle in which the sp...

The radius of the circle in which the sphere `x^(2)+y^(2)+z^(2)+2x-2y-4z-19=0` is cut by the plane `x+2y+2z+7=0` is

A

2

B

3

C

4

D

1

Text Solution

Verified by Experts

The correct Answer is:
b
Center of the sphere is (-1,1,2) and its radius `sqrt(1+1+4+19)=5`
CL, perpendicular distance of C from plane, is

`|(-1+2+4+7)/(sqrt(1+4+4))|=4`
Now, `AL^(2)=CA^(2)-CL^(2)=25-16=9`
Hence, radius of the circle `=sqrt9=3`
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