The equation of the plane passing through lines `(x-4)/1=(y-3)/1=(z-2)/2a n d(x-3)/2=(y-2)/(-4)=z/5` is a. `11 x-y-3z=35` b. `11 x+y-3z=35` c. `11 x-y+3z=35` d. none of these

Options

A. `11x-y-3z=35`
B. `11x+y-3z=35`
C. `11x-y+3z=35`
D. none of these

Answer

d

Explanation

Here, the required plane is
`" "a(x-4)+ b(y-3) + c (z-2)=0`
Also `a+b+2c=0 and a-4b +5c=0`
Solving, we have
`" "(a)/(5+8) = (b)/(2-5) = (c )/(-4-1)= k`
`" "(a)/(13)= (b)/(-3)= (c )/(-5)= k `
Therefore, the required equation of plane is
`" "-13x+3y+5z+33=0`