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Solve |x^2-x-2|+|x+6|=|x^2-2x-8|...

Solve `|x^2-x-2|+|x+6|=|x^2-2x-8|`

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The correct Answer is:
`x in (- oo ,-6 ] cup [-1,2]`
`|x^2-x-2|+|x+6|=|x^2-2x-8|`
or `|x^2-x-2|+|x+6|=(x^2-x-2)-(x+6)|`
or `|x^2-x-2|+|-x-6|=|(x^2-x-2)+(-x-6)|`
or `(x^2-x-2)(-x-6)ge 0 `
or `(x^2-x-2)(x+6) le 0 `
or `(x-2)(x+1)(x+6) le 0 `
or ` x in (-oo,-6] cup [-1,2]`
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