Two flagstaffs stand on a horizontal plane. A and B are two points on the line joining their feet and between them. The angles of elevation of the tops of the flagstaffs as seen from A are `30^@` and` 60^@` and as seen from B are `60^@`and `45^@`. If AB is 30 m, then the distance between the flagstaffs is

Options

A. `30+15sqrt3`
B. `45+15sqrt3`
C. `60-15sqrt3`
D. `60+15sqrt3`

Answer

D

Explanation

Let x and y be the hight of the flagstaffs at P and Q respectively.

Then `AP= x cot 60 ^@ = (x)/(sqrt(3))`
`AQ = y cot 30 ^@= y sqrt(3)`
`BP= x cot 45 ^@ = x`
and `BQ= y cot 60 ^@ = (y)/(sqrt(3)`
`therefore AB=BP- AP= x -(x)/(sqrt(3)`
`rArr 30 sqrt(3)=(sqrt(3)-1)x`
`rArr x= 15 (3 + sqrt(3))`
`Similarly,
30 =y(sqrt(3)-1/sqrt(3))`or `y= 15 sqrt(3)`
`therefore PQ= BP+BQ= x+ y/(sqrt(3))`
`= 15(3+ sqrt(3))+15`
`= (60 + 15 sqrt(3))m`