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If the angles of elevation of the top of a tower from three collinear points A, B and C, on a line leading to the foot of the tower, are `30^0` , `45^0` and `60^0` respectively, then the ratio, AB : BC, is : (1) `sqrt(3):1` (2) `sqrt(3):sqrt(2)` (3) `1:sqrt(3)` (4) `2"":""3`

A

`sqrt(3):1`

B

`sqrt(3):sqrt(2)`

C

`1:sqrt(3)`

D

`2:3`

Text Solution

Verified by Experts

Let ED be the tower of height h.
`tan 30 ^@ = (h) /(AD) `
` rArr AD= h sqrt( 3) `
`BD= h,CD=h/sqrt( 3)`
`(AB)/(BC)=(AD- BD)/(BD-CD)`
`(hsqrt(3)-h)/(h-(h)/sqrt3)=(sqrt(3)-1)/(((sqrt(3)-1)/(sqrt(3))))=sqrt(3)`
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