`L=underset(xto3^(-))lim(x-2)/(x-3)=underset(hto0)lim((3-h)-2)/((3-h)-3)=underset(hto0)lim(1-h)/(-h)` Now when h tends to 'O' , numerator (1-h) moves close to 1 and denominator (-h) moves close to 'O' but negative. Thus, we are dividing 1 with very small negative value. So, the value of the ratio will approach to negative infinity. Therefore, L approaches to `-oo.`
