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If ("lim")(x to0)(a e^x-b)/x = 2 , then ...

If `("lim")_(x to0)(a e^x-b)/x = 2 ,` then find the value of `a and bdot`

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`underset(xto0)lim(ae^(x)-b)/(x)=2`
or`" "underset(xto0)lim(ae^(x)-a+a-b)/(x)=2`
or `" "aunderset(xto0)lim(e^(x)-1)/(x)+underset(xto0)lim(a-b)/(x)=2`
or `" "a+underset(xto0)lim(a-b)/(x)=2`
or `a+b=0`and `a=2`
or `a=2, b=2`
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