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Find the equation of a straight line pas...

Find the equation of a straight line passing through the point `(-5,4)` and which cuts off an intercept of `sqrt(2)` units between the lines `x+y+1=0` and `x+y-1=0.`

Text Solution

Verified by Experts

The correct Answer is:
x-y+9=0
Since the perpendicular distance between the given lines is `sqrt(2)`, the required line is a straight line perpendicular to the given parallel lines and passes through (-5,4).
Any line perpendicular to the given lines is
x-y+k=0
This line passes through (-5,4). Therefore,
-5-4+k = 0
or k=9
Hence, the required line is
x-y+9=0
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