Prove that the parallelogram formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2and x/b+y/a=2` is a rhombus.

Answer

B

Explanation

Clearly, distance between the parallel lines `(x)/(a)+(y)/(b) = 1 " and " (x)/(a) + (y)/(b) = 2 " is same as the distance between the parallel lines "(x)/(b)+(y)/(a) = 1 " and " (x)/(b)+(y)/(b) = 2`.
Therefore, quadrilateral is rhombus.