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The line L1-=4x+3y-12=0 intersects the x...

The line `L_1-=4x+3y-12=0` intersects the x-and y-axies at `Aa n dB ,` respectively. A variable line perpendicular to `L_1` intersects the x- and the y-axis at `P` and `Q` , respectively. Then the locus of the circumcenter of triangle `A B Q` is

A

3x-4y+2 = 0

B

4x+3y+7 = 0

C

6x-8y+7=0

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

Clearly, the circumcenter of triangle ABQ will lie on the perpendicular bisector of line AB. Now, the equation of perpendicular bisector of line AB is 3x-4y+7/2=0. Hence, the locus of circumcenter is 6x-8y+7=0.
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