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The locus of a point that is equidistant...

The locus of a point that is equidistant from the lines `x+y - 2sqrt2 = 0` and `x + y - sqrt2 = 0` is (a) `x+y-5sqrt2=0` (b) `x+y-3sqrt2=0` (c) `2x+2y-3 sqrt2=0` (d) `2x+2y-5sqrt5=0`

A

`x+y-5sqrt(2)=0`

B

`x+y-3sqrt(2)=0`

C

`2x+2y-3sqrt(2) = 0`

D

`2x+2y-5sqrt(2) = 0`

Text Solution

Verified by Experts

The correct Answer is:
C
For any point P (x,y) that is equidistant from the given line, we have
`x+y-sqrt(2) = -(x+y-2sqrt(2))`
`"or " 2x+2y-3sqrt(2) =0`
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