In a triangle A B C , the bisectors of a...

In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=y a n d y=0.` If `A` is `(1,2)` , then the equation of line `B C` is

2x+y=1

3x-y=5

x-2y=3

x+3y=1

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The correct Answer is:

The reflections of A in the two angle bisectors will lie on the line BC, So, (2,1) and (1,-2) will lie on BC. The equation of BC will be
`y+2 = ((1+2)/(2-1))(x-1)`
i.e., 3x-y=5

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