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The equation of the bisector of the acut...

The equation of the bisector of the acute angle between the lines `2x-y+4=0` and `x-2y=1` is

A

x+y+5=0

B

x-y+1=0

C

x-y=5

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

Clearly, from the figure, the origin is contained in the acute angle. Writing the equations of thel lines as 2x-y+4=0 and -x+2y+1=0, the required bisector is
`(2x-y+4)/(sqrt(5)) = (-x+2y+1)/(sqrt(5))`
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