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Consider a triangle PQR with coordinates...

Consider a triangle PQR with coordinates of its vertices as P(-8,5), Q(-15, -19), and R (1, -7). The bisector of the interior angle of P has the equation which can be written in the form ax+2y+c=0. triangle PQR is
The sum a + c is

A

129

B

78

C

89

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
The coordinates of D using section formula are (-5, -23/2) and
`m_(PD) = -11//2.` The equation of PD is
11x+2y+78=0
or a+c = 89
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