If `Aa n dB` are three square matrices of the same order, then `A B=A C B=Cdot` Then `|A|!=0` b. `A` is invertible c. `A` may be orthogonal d. is symmetric

Options

A. `|A| ne 0`
B. A is invertible
C. A may be orthogonal
D. A is symmetric

Explanation

If `|A| ne 0`, then
`AB=AC`
or `A^(-1) AB=A^(-1) AC`
or `B=C`
Also, if A is orthogonal matrix, then `A A^(T)=I`
`implies |A A^(T)|=1 implies |A|^(2)=1implies` is invertible