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if x^(2) !=npi+1, ninN then int x sqrt((...

if `x^(2) !=npi+1`, `ninN` then `int x sqrt((2sin(x^(2)-1)-sin2(x^(2)-1))/(2sin(x^(2)-1)+sin2(x^(2)-1))) dx` is equal to (a) `In cos ((x^(2)-1)/(2))+c` (b) `(1)/(2)In cos ((x^(2)-1)/(2))+c` (c) `In sec ((x^(2)-1)/(2))+c` (d) `(1)/(2)In sec ((x^(2)-1)/(2))+c`

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If x^2!=n pi-1, n in N . Then, the value of int x sqrt((2sin(x^2+1)-sin2(x^2+1))/(2sin(x^2+1)+sin2(x^2+1)))dx is equal to:

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Knowledge Check

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