Home
Class 12
MATHS
Find the equation of tangent to the coni...

Find the equation of tangent to the conic `x^2-y^2-8x+2y+11=0` at `(2,1)`.

Text Solution

Verified by Experts

The equation of the tangent to `x^(2)-y^(2)-8x+2y+11=0` at (2, 1) is
`2x-y-4(x+2)+(y+1)+11=0`
`"or "x=2`
Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    CENGAGE PUBLICATION|Exercise SOLVED EXAMPLES|11 Videos
  • HYPERBOLA

    CENGAGE PUBLICATION|Exercise CONCEPT APPLICATION EXERCISE 7.1|3 Videos
  • HIGHT AND DISTANCE

    CENGAGE PUBLICATION|Exercise Archives|3 Videos
  • INDEFINITE INTEGRATION

    CENGAGE PUBLICATION|Exercise Multiple Correct Answer Type|2 Videos

Similar Questions

Explore conceptually related problems

The equation of the tangent to the conic x^(2)-y^(2)-8x+2y+11=0 at (2,1) is

Find the equation of the normals to the circle x^2+y^2-8x-2y+12=0 at the point whose ordinate is -1

Find the equations of tangents to the circle x^2+y^2-22 x-4y+25=0 which are perpendicular to the line 5x+12 y+8=0

Find the equation of the tangent to the ellipse x^2/a^2+y^2/b^2=1 at (x= 1,y= 1) .

Find the equation of tangents to hyperbola x^(2)-y^(2)-4x-2y=0 having slope 2.

Find the equation of the tangents to the cirlce x^(2)+y^(2)=81 which are perpendicular to the line 4x+3y=0

Find the equation of the tangent to the parabola y^(2)=8x at the point (2t^(2),4t) . Hence find the equation of the tangnet to this parabola, perpendicular to x+2y+7=0

Find the equation of the common tangent to the circle x^(2)+y^(2)=8 and the parabola y^(2)=16x .

Find the equation of the tangent to the curve (1+x^2)y=2-x , where it crosses the x-axis.

Prove that the equation of any tangent to the circle x^2+y^2-2x+4y-4=0 is of the form y=m(x-1)+3sqrt(1+m^2)-2.