On which curve does the perpendicular tangents drawn to the hyperbola `(x^(2))/(25)-(y^(2))/(16)=1` intersect?
Text Solution
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The locus of the point of intersection of prependicular tangents to `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` is the director circle given by `x^(2)+y^(2)=a^(2)-b^(2)` Hence, the perpendicular tangents drawn to `(x^(2))/(25)-(y^(2))/(16)=1` intersect on the curve `x^(2)+y^(2)=25-16=9`
Two perpendicular tangents drawn to the ellipse (x^2)/(25)+(y^2)/(16)=1 intersect on the curve.
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