Let P(6,3) be a point on the hyperbola parabola `x^2/a^2-y^2/b^2=1`If the normal at the point intersects the x-axis at (9,0), then the eccentricity of the hyperbola is
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Normal at (6, 3) to the hyperbola `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` is `(a^(2)x)/(6)+(b^(2)y)/(3)=a^(2)+b^(2)` It passes through (9,0). `therefore" "(9a^(2))/(6)=a^(2)+b^(2)` `rArr" "(b^(2))/(a^(2))=(1)/(2)` `rArr" "e^(2)-1=(1)/(2)` `therefore" "e=sqrt((3)/(2))`
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