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Find the equation of the chord of the hy...

Find the equation of the chord of the hyperbola `25 x^2-16 y^2=400` which is bisected at the point (5, 3).

Text Solution

Verified by Experts

The correct Answer is:
`125x-48y=481`
The equation of the given hyperbola can be written as
`(x^(2))/(16)-(y^(2))/(25)=1`
Therefore, the equation of the chord of this hyperbola whose midpoint is (5, 3) is
`(5x)/(16)-(3y)/(25)-1=(5^(2))/(16)-(9)/(25)-1`
`"or "125x-48y=481`
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