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The equation (x-alpha)^2+(y-beta)^2=k(l ...

The equation `(x-alpha)^2+(y-beta)^2=k(l x+m y+n)^2` represents

A

a parabola for `k lt(l^(2)+m^(2))^(-1)`

B

an ellipse for `0 lt k lt(l^(2)+m^(2))^(-1)`

C

a hyperbola for `k gt (l^(2)+m^(2))^(-1)`

D

a point circle for k = 0

Text Solution

Verified by Experts

The correct Answer is:
B, C, D

`(x-alpha)^(2)+(gamma-beta)^(2)=k(lx+my+n)^(2)`
`"or "sqrt((x-alpha)^(2)+(y-beta)^(2))=sqrtksqrt(l^(2)+m^(2))((lx+my+n))/(sqrt(l^(2)+m^(2)))`
`"or "(PS)/(PM)=sqrtksqrt(l^(2)+m^(2))`
where P(x, y) is any point on the curve.
Fixed `S(alpha, beta)` is focus and fixed line `lx+my+n=0` is directrix.
If `k(l^(2)+m^(2))=1, P` lies on a parabola.
If `k(l^(2)+m^(2))lt1`, P lies on an ellipse.
If `k(l^(2)+m^(2))gt1`, P lies on a hyperbola.
If k = 0, P lies on a point circle.
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