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Find the value of m for which y=mx+6 is ...

Find the value of m for which `y=mx+6` is a tangent to the hyperbola `(x^(2))/(100)-(y^(2))/(49)=1.`

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The correct Answer is:
2
Equation of tangent to hyperbola `(x^(2))/(5)-(y^(2))/(b^(2))=1` having slope m is
`y=mx pm sqrt(a^(2)m^(2)-b^(2))`
`rArr" "y=xpmsqrt(5-b^(2))`
Comparing with y = x+1, we get
`b^(2)=4 or b = pm2`
So, two value are possible.
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