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Area of the regular hexagon whose diagon...

Area of the regular hexagon whose diagonal is the join of `(2, 4) and (6,7)` is

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The correct Answer is:
`(75sqrt3)/(8)`sq.unit
We have A(2,4)and B(6,7) as end points diaginal of the hexagon. ` therefore AB=5`
Thus length of the line segment joining centre of the hexagon and one of the vertices is `(5/2)`.
`therefore` Area of hexagon `=6xx` Area of equilateral triangle having side length ` (5/2)`
`=6xx(sqrt3)/(4)xx(25)/(4)=(75sqrt3)/(8)`
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