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The line joining A (b cos alpha, b sin a...

The line joining A `(b cos alpha, b sin alpha )` and B `(a cos beta, a sin beta)`, where `a ne b`, is produced to the point M(x,y) so that AM :MB = b :a Then `xcosfrac(alpha+beta)(2)+ysinfrac(alpha+beta)(2)`

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The correct Answer is:
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`(cos alpha,b sinalpha)alphacosbeta,a sinbeta)`
`(AM)/(BM)=(b)/(a)`
`therefore M((abcosalpha-abcosbeta)/(a-b),(ab sin alpha-ab sin beta)/(a-b))-=M(x,y)`
`rArr(x/y)
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