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The medians AD and BE of a triangle ABC ...

The medians AD and BE of a triangle ABC with vertices A(0, b), B(0, 0) and C(a, 0) are perpendicular to each other if `a^2:b^2` is

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The correct Answer is:
NA

From the figure,
Slope of `BE,m_(BE)=(b)/(a)`
Slope of `AD,m_(AD)=-(2b)/(a)`
Given that AD and BE are perpendicular.
`therefore m_(BE)xxm_(AD)=-(2b^2)/(a^2)=-1`
`rArra^2=2b^2`
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