Home
Class 12
MATHS
Convert 2x^2+3y^2=6 into the polar equat...

Convert `2x^2+3y^2=6` into the polar equation.

Text Solution

Verified by Experts

The correct Answer is:
`r^2(2+sin^2theta)=6`
`2x^2+3y^2=6`
or `2(rcostheta)^2+3(rsintheta)^2=6`
or `2r^2cos^2theta+3r^2sin^2theta=6`
or `2r^2+r^2sin^2theta=6`
or `r^2(2+sin^2theta)=6`
Promotional Banner

Topper's Solved these Questions

  • COORDINATE SYSYEM

    CENGAGE PUBLICATION|Exercise Concept applications 1.6|9 Videos

  • COORDINATE SYSYEM

    CENGAGE PUBLICATION|Exercise Exercises|59 Videos

  • COORDINATE SYSYEM

    CENGAGE PUBLICATION|Exercise Concept applications 1.4|8 Videos

  • COORDINATE SYSTEM

    CENGAGE PUBLICATION|Exercise Multiple Correct Answers Type|2 Videos

  • CROSS PRODUCTS

    CENGAGE PUBLICATION|Exercise DPP 2.2|13 Videos

Similar Questions

Explore conceptually related problems

Convert x^2-y^2=4 into a polar equation.

Convert y=10 into a polar equation.

Convert (1+3i)/(1-2i) into the polar form.

Find the equation of the plane passing through the points (1,1,2) and (2,4,3) and prependicular to the plane x-3y+7z=6 , convert the equation to vector from.

Convert the following in the polar form (1+3i)/(1-2i)

Find the value of k, if x = 2, y =1 is a solution of the equation 2x + 3y = k. Find two more solutions of the resultant equation.

For hyperbola whose center is at (1, 2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1 , the equation of the hyperbola passing through (2, 4) is (a) (2x+3y-5)(x+2y-8)=40 (b) (2x+3y-8)(x+2y-5)=40 (c) (2x+3y-8)(x+2y-5)=30 (d) none of these

Two circle x^2+y^2=6 and x^2+y^2-6x+8=0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is x^2+y^2-6x+4=0 x^2+y^2-3x+1=0 x^2+y^2-4y+2=0 none of these

(ii) The polar form of the equation (x^2+y^2)^(3/2)=a(x^2-y^2) in the Cartesian form is

Solve by matrix inversion method the following system of equations. 2x + y = 2, 3x + y = 6