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In (3 3+1/(3 3))^n if the ratio of 7th t...

In `(3 3+1/(3 3))^n` if the ratio of 7th term from the beginning to the 7th term from the end is 1/6, then find the value of `ndot`

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The correct Answer is:
`n = 9`
`1/6 = (.^(n)C_(6)(2^(1//3))^(n-6)(3^(-1//3))^(6))/(.^(n)C_(n-6)(2^(1//3))^(n-6)(3^(-1//3))^(n-6))`
`6^(-1) = 6^(-4) xx 6^(n//3)= 6^(n//3-4) rArr n/3 - 4 = - 1 rArr n = 9`
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CENGAGE PUBLICATION-BINOMIAL THEOREM-Concept Application Exercise 8.1
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