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Find the value of (sumsum)(0leiltjlen) ...

Find the value of `(sumsum)_(0leiltjlen) (i+j)(""^(n)C_(i)+""^(n)C_(j))`.

A

`an^(2)`

B

`(a^(2)n)/(2)`

C

`a^(2)n`

D

`(n^(2)a)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`S = underset(0leiltjlen)(sumsum)((i)/(.^(n)C_(i))+(j)/(.^(n)C_(j)))`
`= underset(0leiltjlen)(sumsum)((n-i)/(.^(n)C_(n-i))+(n-j)/(.^(n)C_(n-j)))`
`= n underset(0leiltjlen)(sumsum)((1)/(.^(n)C_(i))+(1)/(.^(n)C_(j)))-S`
`rArr S = n/2underset(0leiltjlen)(sumsum) ((1)/(.^(n)C_(i))+(1)/(.^(n)C_(j)))`
`=n/2(underset(r=0)overset(n-1)sum(n-r)/(.^(n)C_(r))+underset(r=1)overset(n)sum(r)/(.^(n)C_(r)))`
`= n/2(overset(n)underset(r=0)sum(n)/(.^(n)C_(r))) = (n^(2)a)/(2)`
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