Ina certain town, 40% of the people have brown hair, 25% have brown eyes, and 15% have both brown hair and brown eyes. If a person selected at random from the town has brown hair, the probability that he also has brown eyes is `1//5` b. `3//8` c. `1//3` d. `2//3`

Options

A. `1//5`
B. `3//8`
C. `1//3`
D. `2//3`

Answer

B

Explanation

We have, `P(A)=40/100,P(B)=25/100and P(AnnB)=15/100`
So, `P((B)/(A))=(P(AnnB))/(P(A))=(15//100)/(40//100)=3/8`