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All the jacks, queens, kings, and aces o...

All the jacks, queens, kings, and aces of a regular 52 cards deck are taken out. The 16 cards are throughly shuffled and may opponent, a person who always tells the truth, simultaneously draws two cards at random and says, "I hold at least one ace". The probability that he holds two aces is (a)2/8 (b)4/9 (c)2/3 (d)1/9

A

`2//8`

B

`4//9`

C

`2//3`

D

`1//9`

Text Solution

Verified by Experts

The correct Answer is:
D
A: exactly oen ace
B: both aces
E: `AuuB`
`P(B//AuuB)=(""^(4)C_(2))/(""^(4)C_(1)""^(12)C_(1)+""^(4)C_(2))=6/54=1/9`
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