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A parabola mirror is kept along y^2=4x a...

A parabola mirror is kept along `y^2=4x` and two light rays parallel to its axis are reflected along one straight line. If one of the incident light rays is at 3 units distance from the axis, then find the distance of the other incident ray from the axis.

Text Solution

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We have parabola `y^(2)=4x`.
Let two incident rays AP and BQ, which are parallel to axis of the parabola, strikes the parabola at points A and B, respectively.
After reflection, both the pass through the focus S(1,0).

Therefore, AB is focal chord.
Let point A be `(t^(2),2t)`.
Distance of ray AP is 3 units from axis.
`:." "2t=3`
`or" "t=(3)/(2)`
Coordinates of point B are `((1)/(t^(2)),(-2)/(t))` (other end of focal chord).
Distance of B from the axis `=(2)/(t)=(4)/(3)`
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Knowledge Check

  • A ray light along x+sqrt3y = sqrt3 gets reflected upon reaching the x-axis, the equation of the reflected ray is

    A
    `sqrt3y =x-1`
    B
    `y=sqrt3x-sqrt3`
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    `sqrt3y= x-sqrt3`
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    `2x-3y=4`
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    `3x+2y=4`
    C
    `3x-2y=4`
    D
    `3x-2y+4=0`
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