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The triangle P Q R of area A is inscribe...

The triangle `P Q R` of area `A` is inscribed in the parabola `y^2=4a x` such that the vertex `P` lies at the vertex of the parabola and the base `Q R` is a focal chord. The modulus of the difference of the ordinates of the points `Qa n dR` is

A

A/2a

B

A/a

C

2A/a

D

4A/a

Text Solution

Verified by Experts

The correct Answer is:
C

(3) Difference of the ordinate
`d=|2at+(2a)/(t)|=2a|t+(1)/(t)|`

Now, area `(A)=(1)/(2)|(at^(2),2at,1),(a//t^(2),-2a//t,1),(0,0,1)|=a^(2)(t+(1)/(t))`
`or2a(t+(1)/(t))=(2A)/(a)`
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