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y=x+2 is any tangent to the parabola y^2...

`y=x+2` is any tangent to the parabola `y^2=8xdot` The point `P` on this tangent is such that the other tangent from it which is perpendicular to it is (a)`(2,4)` (b) `(-2,0)` (c)`(-1,1)` (d) `(2,0)`

A

(2,4)

B

(-2,0)

C

(-1,1)

D

(2,0)

Text Solution

Verified by Experts

The correct Answer is:
B
(2) Clearly, P is the point of intersection of two perpendicular tangents to the parabola `y^(2)=8x`.
Hence, P must lie on the directrix x+a=0orx+2=0.
Therefore, x=-2.
Hence, the point is (-2,0).
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CENGAGE PUBLICATION-PARABOLA-EXERCISE (SINGLE CORRECT ANSWER TYPE )
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  2. The angle between tangents to the parabola y^2=4ax at the points where...

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