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G is the centroid of triangle ABC and ...

`G` is the centroid of triangle `ABC` and `A_1` and `B_1` are the midpoints of sides `AB` and `AC` , respectively. If `Delta_1` is the area of quadrilateral `G A_1A B_1` and `Delta` is the area of triangle `ABC` , then `Delta/Delta_1` is equal to
a.`3/2`
b. `3`
c. `1/3`
d. none of these

A

`3/2`

B

3

C

`1/3`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
b

Let P.V. of A, B and C be `vec0,vecb and vecc`, respectively therefore,
`vecG = (vecb +vecc) /3`
`vecA_(1) = vecb/2, vecB_(1) = vecc/2`
`Delta_(AB_(1)G) = 1/2 |vec(AG)xx vec(AB_(1))|`
`1/2 |(vecb+vecc)/3 xx (vecc/2)|`
`1/12 |vecb xx vecc|`
`Delta_(AA_(1)G) = 1/2 |vec(AG) xx vec(AA_(1))|= 1/2 |(vecb + vecc)/3 xx (vecb/2)|`
`1/12 |vecb xx vecc|`
`Rightarrow Delta_(GA_(1)AB_(1) = 1/6 |vecb xx vecc| = 1/3. 1/2 |vecb xx vecc|`
`1/3 Delta_(ABC)`
`Rightarrow Delta/Delta_(1) = 3 `
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