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if vecalpha||( vecbetaxx vecgamma) , th...

if ` vecalpha||( vecbetaxx vecgamma)` , then `( vecalphaxxbeta).(vecalphaxx vecgamma)` equals to a.`| vecalpha|^2( vecbeta.vecgamma)` b. `| vecbeta|^2( vecgamma. vecalpha)` c. `| vecgamma|^2( vecalpha. vecbeta)` d. `| vecalpha|| vecbeta|| vecgamma|`

A

`|vecalpha|^(2)(vecbeta.vecgamma)`

B

`|vecbeta|^(2)(vecgamma.vecalpha)`

C

`|vecgamma|^(2)(vecalpha.vecbeta)`

D

`|vecalpha||vecbeta||vecgamma|`

Text Solution

Verified by Experts

The correct Answer is:
a
`vecalpha|| (vecbeta xx vecgamma) Rightarrow vecalpha bot vecbeta and vecalpha bot vecgamma`
now `, ( vecalpha xx vecbeta) . (vecbeta. Vecbeta)`
`= |vecalpha| ( vecbeta. Vecgamma) - (vecalpha. Vecbeta) (vecalpha. Vecgamma)`
` |vecalpha|^(2) . (vecbeta. vecgamma)`
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CENGAGE PUBLICATION-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -Exercises MCQ
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