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If veca + 2 vecb + 3 vecc = vec0 " then...

If `veca + 2 vecb + 3 vecc = vec0 " then " veca xx vecb + vecb xx vecc + vecc xx veca= `

A

`2 (veca xx vecb)`

B

` 6( vecb xx vecc)`

C

`3 ( vecc xx veca)`

D

`vec0`

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The correct Answer is:
c,d

we know that `veca + vecb + vecc = vec0` then
`veca xx vecb =vecb xx vecc = vecc xx veca`
Given `veca + 2vecb + 3 vecc = vec0`
`2 veca xx vecb = 6 vecb xx vecc = 3 vecc xx veca`
Hence `veca xx vecb + vecb xx vecc + vecc xx veca `
` 2 (veca xx vecb) or 6 (vecb xx vecc) or 3 (vecc xx veca)`
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CENGAGE PUBLICATION-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -Exercises MCQ
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