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Let veca= 2 hati + 3hatj - 6hatk, vecb =...

Let `veca= 2 hati + 3hatj - 6hatk, vecb = 2hati - 3hatj + 6hatk and vecc = -2 hati + 3hatj + 6hatk`. Let `veca_(1)` be the projection of `veca` on `vecb and veca_(2)` be the projection of `veca_(1)` on `vecc` . Then
`veca_(1).vecb` is equal to (A) `-41` (B) `-41//7` (C) 41 (D)287

A

`-41`

B

`-41//7`

C

41

D

287

Text Solution

Verified by Experts

The correct Answer is:
a
`veca_(1).vecb= (-41)/49 (2hati - 3hatj + 6hatk) . (2hati - 3hatj + 6hatk) =-41`
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