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Let veca= 2 hati + 3hatj - 6hatk, vecb =...

Let `veca= 2 hati + 3hatj - 6hatk, vecb = 2hati - 3hatj + 6hatk and vecc = -2 hati + 3hatj + 6hatk`. Let `veca_(1)` be the projection of `veca` on `vecb and veca_(2)` be the projection of `veca_(1)` on `vecc` . Then
`veca_(2)` is equal to (A) `943/49 (2 hati - 3hatj - 6hatk)` (B) `943/(49^(2)) (2 hati - 3hatj - 6hatk)` (C) `943/49 (-2 hati + 3hatj + 6hatk)` (D) `943/(49^(2)) (-2 hati + 3hatj + 6hatk)`

A

`veca and vcea_(2)` are collinear

B

`veca_(1) and vecc` are collinear

C

`veca m veca_(1) and vecb` are coplanar

D

`veca, veca_(1) and a_(2)` are coplanar

Text Solution

Verified by Experts

The correct Answer is:
c

`veca,veca_(1)andvecb` are coplanar because `veca_(1) and vecb` are collinear.
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CENGAGE PUBLICATION-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -Comprehension type
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