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Given two vectors veca= -hati +hatj + 2h...

Given two vectors `veca= -hati +hatj + 2hatk and vecb =- hati - 2 hatj -hatk`
find `|vec a xx vec b|`

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The correct Answer is:
`a to s ; b to r; c to q ; d to p`
a. `vecaxxvecb=|{:(hati,hatj,hatk),(-1,1,2),(-1,-2,-1):}|=3hati'-3hatj+3hatk`
Hence, the area of the triangle is `(3sqrt3)/2`
b. The area of the parallelogram is `3sqrt3`
c. The area of a paralleogram whose diagonals are
`2 veca and 4vecb is 1/2 |2 veca xx 4vecb|=12sqrt3`
d. volume of the parallelpiped
`= |(veca xx vecb).vecc|=sqrt(9+36+9)= 3sqrt6`
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