If ` vec a , vec ba n d vec c` are unit coplanar vectors, then the scalar triple product `[2 vec a- vec b2 vec b- vec c2 vec c- vec a]` is `0` b. `1` c. `-sqrt(3)` d. `sqrt(3)`

Options

A. 0
B. 1
C. `-sqrt3`
D. `sqrt3`

Answer

a

Explanation

`veca vecb and vecc` are unit coplanar vectors, `2veca- vecb , 2vecb - 2vecc and 2vecc - veca` are also coplanar, vectors ], being a linear combination of `veca , vecb and vecc` thus ` [ 2 veca - vecb 2vecb - vecc 2vecc - veca] =0`