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Let ` vec a=2 hati+hat j+ hat k , vec b=hat i+2hat j- hatk` and a unit vector ` vec c` be coplanar. If ` vec c` is perpendicular to ` vec a ,` then ` vec c` is a.`1/(sqrt(2))(-hat j+hat k)` b. `1/(sqrt(3))(-hat i-hat j-hat k)""` c. `1/(sqrt(5))(-hat k-2 hat j)` d. `1/(sqrt(3))(hat i-hat j- hat k)`

A

`1/sqrt2(-j+k)`

B

`1/sqrt3(i-j-k)`

C

`1/sqrt5(i-2j)`

D

`1/sqrt3(i-j-k)`

Text Solution

Verified by Experts

The correct Answer is:
a

As `vecc` is coplanar with `veca and vecb` we take
`vecc = alpha veca + betavecb`
where `alpha and beta` are scalars.
As `vecc` is perpendicular to `veca` , using (i), we get
`0 = alphaveca.veca +betavecb.veca`
`or 0 =alpha (6) +beta(2+2-1) =3 (2alpha+beta) `
`or beta = -2alpha`
Thus `vecc=alpha(veca -2vecb)=alpha(-3j+3k)=3alpha(-j+k)`
`or |vecc|^(2)=18alpha^(2)`
`or 1=18alpha^(2)`
`or alpha= +- 1/(3sqrt2)`
`vecc =+- 1/sqrt2 (-j+k)`
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CENGAGE PUBLICATION-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -single correct answer type
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